octavio_dingus@lemmy.world to Technology@lemmy.worldEnglish · 22 hours agoReddit temporarily bans r/WhitePeopleTwitter after Elon Musk claimed it had ‘broken the law’www.engadget.comexternal-linkmessage-square44fedilinkarrow-up1390arrow-down19
arrow-up1381arrow-down1external-linkReddit temporarily bans r/WhitePeopleTwitter after Elon Musk claimed it had ‘broken the law’www.engadget.comoctavio_dingus@lemmy.world to Technology@lemmy.worldEnglish · 22 hours agomessage-square44fedilink
minus-squareVintageGenious@sh.itjust.workslinkfedilinkEnglisharrow-up1arrow-down5·15 hours agoBroken clock as speed isn’t right or offset? Doesn’t seem to work
minus-squareprole@lemmy.blahaj.zonelinkfedilinkEnglisharrow-up1·3 hours agoI’ve always heard the saying as “a stopped clock.”
minus-squareqantravon@lemmy.worldlinkfedilinkEnglisharrow-up9·15 hours agoFor the phrase, “broken” specifically means “stopped”, and the clock is analog. If the hands don’t turn, then they will be correct twice per day.
minus-squareVintageGenious@sh.itjust.workslinkfedilinkEnglisharrow-up1·edit-257 minutes agoThanks makes more sense! Idk why the downvotes… Because in the case of an offset it would always be wrong and in the case of a speed change. In the general case, with clock speed a and offset b: a x + b ≡ x (mod 12) a x + b = x + 12k If a=1, normal speed with offset, b = 12k ≡ 0 (mod 12) So it works for any multiple of 12h offset (ie no offset) If a≠1, x = (12k - b)/(a-1) It isn’t always in a day, so you can end up having to wait multiple days for it to be right
Broken clock as speed isn’t right or offset? Doesn’t seem to work
I’ve always heard the saying as “a stopped clock.”
For the phrase, “broken” specifically means “stopped”, and the clock is analog. If the hands don’t turn, then they will be correct twice per day.
Thanks makes more sense! Idk why the downvotes… Because in the case of an offset it would always be wrong and in the case of a speed change.
In the general case, with clock speed a and offset b:
If a=1, normal speed with offset,
So it works for any multiple of 12h offset (ie no offset)
If a≠1,
It isn’t always in a day, so you can end up having to wait multiple days for it to be right